Vector Mechanics For Engineers Statics 12th Edition Solutions Now

R = √(Rx^2 + Ry^2) = √(161.60^2 + 179.90^2) = 243.30 N θ = tan^(-1)(Ry/Rx) = tan^(-1)(179.90/161.60) = 48.19°

Calculate the magnitude of the moment.

MO = (3(0) - 4(0))i - (2(0) - 4(200))j + (2(0) - 3(200))k = 0i + 800j - 600k R = √(Rx^2 + Ry^2) = √(161

Find the resultant force components.