Hybridization Of So42 [work] Jun 2026

To explain the tetrahedral geometry of SO42-, we need to consider the hybridization of the sulfur atom. The sulfur atom undergoes , which involves the mixing of one s orbital (3s) and three p orbitals (3px, 3py, and 3pz).

To form the sulfate ion, sulfur is bonded to four oxygen atoms. The sulfur atom shares its four valence electrons with four oxygen atoms, forming four equivalent σ bonds. hybridization of so42

In the sulfate ion, the sulfur atom is bonded to four oxygen atoms. To accommodate these four bonds, the sulfur atom undergoes hybridization. To explain the tetrahedral geometry of SO42-, we

. To accommodate the four bonds and maintain formal charge stability, sulfur promotes electrons to its empty The four sp3s p cubed hybrid orbitals overlap with oxygen orbitals to form four Pi ( ) Bonds: The two remaining unpaired electrons in sulfur's orbitals form The sulfur atom shares its four valence electrons

= number of atoms bonded to central atom + number of lone pairs on central atom.